m^2-17=3m

Solution for m^2-17=3m equation:

m^2-17=3m

We move all terms to the left:

m^2-17-(3m)=0

a = 1; b = -3; c = -17;
Δ = b2-4ac
Δ = -32-4·1·(-17)
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{77}}{2*1}=\frac{3-\sqrt{77}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{77}}{2*1}=\frac{3+\sqrt{77}}{2}
$